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NEW QUESTION: 1
A new hire wants to use a personally owned phone to access company resources. The new hire expresses concern about what happens to the data on the phone when they leave the company. Which of the following portions of the company's mobile device management configuration would allow the company data to be removed from the device without touching the new hire's data?
A. Asset control
B. Device access control
C. Storage segmentation
D. Storage lock out
Answer: B
NEW QUESTION: 2
Sie haben eine Hybridbereitstellung von Microsoft 365, die die in der folgenden Tabelle aufgeführten Benutzer enthält.
Sie haben eine lokale Web-App namens App
Sie konfigurieren einen Azure Active Directory-Anwendungsproxy (Azure AD).
Sie fügen einen Anwendungsproxy-Eintrag für AppA hinzu, wie im Exponat gezeigt. (Klicken Sie auf die Registerkarte Ausstellung.)
Sie weisen die AppA-Unternehmensanwendung in Azure Gruppe2 zu.
Wählen Sie für jede der folgenden Aussagen Ja aus, wenn die Aussage wahr ist. Andernfalls wählen Sie Nein.
HINWEIS: Jede richtige Auswahl ist einen Punkt wert.
Answer:
Explanation:
Explanation:
Box 1: No
User1 is in Group2. The enterprise app is assigned to Group2. However, the authentication method is "Passthrough" so the authentication will be passed to the on-premises web app. Only Group1 has access to the web app. Therefore, User1 will not be able to access the web app.
Box 2: Yes.
User2 is in Group1 and Group2. The enterprise app is assigned to Group2. The authentication method is "Passthrough" so the authentication will be passed to the on-premises web app. Group1 has access to the web app. Therefore, User2 will be able to access the web app in MyApps.
Box 3: No
User3 is in Group1. Group1 has access to the web app so User3 could access the app on-premises. However, the enterprise app is assigned to Group2 which User3 is not a member of. Therefore, User3 will not be able to access the external URL of the web app.
NEW QUESTION: 3
A. STORED AS TEXTFILE
B. STORED AS ORC
C. STORED AS GZIP
D. STORED AS RCFILE
Answer: B
Explanation:
Explanation
The Optimized Row Columnar (ORC) file format provides a highly efficient way to store Hive data. It was designed to overcome limitations of the other Hive file formats. Using ORC files improves performance when Hive is reading, writing, and processing data.
Compared with RCFile format, for example, ORC file format has many advantages such as:
* a single file as the output of each task, which reduces the NameNode's load
* Hive type support including datetime, decimal, and the complex types (struct, list, map, and union)
* light-weight indexes stored within the file
* skip row groups that don't pass predicate filtering
* seek to a given row
* block-mode compression based on data type
* run-length encoding for integer columns
* dictionary encoding for string columns
* concurrent reads of the same file using separate RecordReaders
* ability to split files without scanning for markers
* bound the amount of memory needed for reading or writing
* metadata stored using Protocol Buffers, which allows addition and removal of fields
NEW QUESTION: 4
What happens when you attempt to compile and run the following code?
#include <deque>
#include <iostream>
#include <algorithm>
#include <set>
using namespace std;
template<class T>struct Out {
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out<<val<<" "; }
};
bool Compare(char a, char b) { return tolower(a) < tolower(b);}
int main() {
char s[]={"qwerty"};
char t1[]={"ert"};
char t2[]={"ERT"};
sort(s, s+6);
cout<<includes(s,s+6, t1,t1+3, Compare)<<" "<<includes(s,s+6, t2,t2+3, Compare)<<endl; return 0;
}
Program outputs:
A. 0 1
B. 0 0
C. 1 0
D. 1 1
Answer: D
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