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HP HPE0-G01 - HPE GreenLake Administrator Essentials Exam Braindumps

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  • Certification Provider:HP
  • Exam Code:HPE0-G01
  • Exam Name:HPE GreenLake Administrator Essentials Exam Exam
  • Total Questions:276 Questions and Answers
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NEW QUESTION: 1

A. Option D
B. Option B
C. Option E
D. Option A
E. Option C
Answer: B,E

NEW QUESTION: 2
Einer Ihrer größten Kunden ist der Einzelhandelspreisliste zugeordnet. Sie haben gerade Mengenrabatte für diesen Kunden für bestimmte Artikel ausgehandelt, die auf den Händlerpreislistenpreisen basieren. Diese zusätzlichen Rabatte sollten nur für diesen Kunden gelten.
Welches ist die beste Preisoption, um dieses Szenario zu unterstützen?
A. Erstellen Sie eine Rabattgruppe nur für diesen Kunden.
B. Richten Sie für diesen Kunden Sonderpreise für Geschäftspartner ein.
C. Fügen Sie Einträge zu den Perioden- und Mengenrabatten für die Händlerpreisliste hinzu.
D. Weisen Sie den Kunden der Händlerpreisliste zu.
Answer: D

NEW QUESTION: 3
The ideal performance state includes all of the following EXCEPT?
A. Absence of fear
B. A sense of effortlessness
C. A wide focus of attention
D. A distortion of time and space
Answer: C

NEW QUESTION: 4
Consider the following database table:
Inventory Table
*Item_ID, Integer: PK
*Item_name, Varchar (20)
*Price, Numeric (10, 2)
*Quan, Integer
Consider the following method that updates the prices in the Inventory table:
public static void updatePrices{ // #1: missing line
Connection con) throws SQLException {
// #2: missing line
PreparedStatement updatePrices = con.prepareStatement (updatePricesString);
// #3: missing line { // #4: missing line updatePrices.executeUpdate();
}
}
This method us missing four lines, which group of lines complete this method?
A. 1. HashMap newPrices,
2.StringupdatePriceString = "UPDATE inventory SET price =? Where item_id '?' ";
3.For (Integer x: newPrice)
4.updatePrice.setInt(1, x);
B. 1. HashMap newPrices,
2.StringupdatePriceString ="UPDATE inventory SET price =? WHERE item_id '?'";
3.For (map.Entry x : newPrices.entrySet())
4.UpdatePrices.setFloat(1, x.getvalue().floatValue()); updatePrice.setString (2, x.getKey().intValue());
C. 1. HashMap newPrices,
2.StringupdatePriceString = "UPDATE inventory SET price =? Where item_id '?' ";
3.For (map.Entry x : newPrices.entrySet())
4.UpdatePrices.setInt(1, x.getvalue().floatValue()); updatePrice.setString (2, x.getvalue());
D. 1. HashMap newPrices,
2.StringupdatePriceString = "UPDATE inventory SET price =? Where item_id '?' ";
3.For (map.Entry x : newPrices.entrySet())
4.UpdatePrices,setString(1, x.getKey()); updatePrices.setFloat(2, x.getValue().floatValue());
E. 1. HashMap newPrices,
2.StringupdatePriceString = "UPDATE inventory SET price =? Where item_id '?' ";
3.For (map.Entry x : newPrices.entrySet())
4.UpdatePrices.setInt(1, x.getvalue().floatValue()); updatePrice.setString (2, x.getvalue().floatValue()
F. 1. HashMap newPrices,
2.StringupdatePriceString ="UPDATE inventory SET price =? WHERE item_name'?'";
3.For (map.Entry x : newPrices.entrySet())
4.UpdatePrices.setFloat(1, x.getvalue().floatValue()); updatePrice.setString (2, x.getKey());
Answer: E
Explanation:
The first line should be HashMap<Integer, Float> newPrices,
as in SQL numeric represent a float number, not an integeror string.
We also make sure to use floatValue() both in appropriate places in line 4.
Note: Map is an object that maps keys to values. A map cannot contain duplicate keys: Each key
can map to at most one value. It models the mathematical function abstraction.

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