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NEW QUESTION: 1
ON NO: 209 DRAG DROP
VNet1およびVNet2という名前の2つの仮想ネットワークを含むAzureサブスクリプションがあります。 仮想マシンは仮想ネットワークに接続します。
仮想ネットワークには、次の表に示すように構成されたアドレススペースとサブネットがあります。

10.33.0.0/16のアドレススペースをVNet1に追加する必要があります。 ソリューションでは、VNet1とVNet2上のホストが通信できることを確認する必要があります。
順番に実行する必要がある3つのアクションはどれですか？ 回答するには、適切なアクションをアクションのリストから回答エリアに移動し、正しい順序に並べます。

Answer:
Explanation:

Explanation

Step 1: Remove peering between Vnet1 and VNet2.
You can't add address ranges to, or delete address ranges from a virtual network's address space once a virtual network is peered with another virtual network. To add or remove address ranges, delete the peering, add or remove the address ranges, then re-create the peering.
Step 2: Add the 10.44.0.0/16 address space to VNet1.
Step 3: Recreate peering between VNet1 and VNet2
References:
https://docs.microsoft.com/en-us/azure/virtual-network/virtual-network-manage-peering

NEW QUESTION: 2
A project manager is managing a project with a hard deadline in two weeks. At the current rate of progress, the project will not finish on time.
Which of the following techniques is MOST likely to be used to complete the project on time?
A. Resource leveling
B. Resource smoothing
C. Crashing
D. Throttling
Answer: C
Explanation:
Explanation/Reference:
References: Kim Heldman, CompTIA Project+ Study Guide, 2nd Edition, Sybex, Indianapolis, 2017, p. 170

NEW QUESTION: 3
Which service on the HP VAN SDN Controller allows Observation posts to be set on a network?
A. Path Daemon Service
B. Topology Service
C. Path Diagnostic Service
D. Network Node Service
Answer: C
Explanation:
Reference: http://h20565.www2.hp.com/portal/site/hpsc/template.BINARYPORTLET/public/kb/docDisplay/res
ource.process/?spf_p.tpst=kbDocDisplay_ws_BI&spf_p.rid_kbDocDisplay=docDisplayResURL&ja vax.portlet.begCacheTok=com.vignette.cachetoken&spf_p.rst_kbDocDisplay=wsrpresourceState%3DdocId%253Demr_na-c040031142%257CdocLocale%253D&javax.portlet.endCacheTok=com.vignette.cachetoken (page 21)

NEW QUESTION: 4
Which two forms of abstraction can a programmer use in Java?
A. abstract classes
B. enums
C. primitive wrappers
D. interfaces
E. primitives
F. concrete classes
Answer: A,D
Explanation:
When To Use Interfaces
An interface allows somebody to start from scratch to implement your interface or implement your interface in some other code whose original or primary purpose was quite different from your interface. To them, your interface is only incidental, something that have to add on to the their code to be able to use your package. The disadvantage is every method in the interface must be public. You might not want to expose everything.
*When To Use Abstract classes
An abstract class, in contrast, provides more structure. It usually defines some default implementations and provides some tools useful for a full implementation. The catch is, code using it must use your class as the base. That may be highly inconvenient if the other programmers wanting to use your package have already developed their own class hierarchy independently. In Java, a class can inherit from only one base class. *When to Use Both
You can offer the best of both worlds, an interface and an abstract class. Implementors can ignore your abstract class if they choose. The only drawback of doing that is calling methods via their interface name is slightly slower than calling them via their abstract class name.
Reference: http://mindprod.com/jgloss/interfacevsabstract.html