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NEW QUESTION: 1
You have a database named DB1.
You plan to create a stored procedure that will insert rows into three different tables. Each insert must use the same identifying value for each table, but the value must increase from one invocation of the stored procedure to the next.
Occasionally, the identifying value must be reset to its initial value.
You need to design a mechanism to hold the identifying values for the stored procedure to use.
What should you do?
More than one answer choice may achieve the goal. Select the BEST answer.
A. Create a sequence object that holds the next value in the sequence. Retrieve the next value by using the stored procedure. Increment the sequence object to the next value by using an ALTER SEQUENCE statement. Reset the value as needed by using a different ALTER SEQUENCE statement.
B. Create an identity column in each of the three tables. Use the same seed and the same increment for each table. Insert new rows into the tables by using the stored procedure. Use the DBCC CHECKIDENT command to reset the columns as needed.
C. Create a sequence object that holds the next value in the sequence. Retrieve the next value by using the stored procedure. Reset the value by using an ALTER SEQUENCE statement as needed.
D. Create a fourth table that holds the next value in the sequence. At the end each transaction, update the value by using the stored procedure. Reset the value as needed by using an UPDATE statement.
Answer: C
Explanation:
Explanation/Reference:
Explanation:
* an application can obtain the next sequence number without inserting the row by calling the NEXT VALUE FOR function.
* ALTER SEQUENCE
Includes argument:
RESTART [ WITH <constant> ]
The next value that will be returned by the sequence object. If provided, the RESTART WITH value must be an integer that is less than or equal to the maximum and greater than or equal to the minimum value of the sequence object. If the WITH value is omitted, the sequence numbering restarts based on the original CREATE SEQUENCE options.
* CREATE SEQUENCE
Creates a sequence object and specifies its properties. A sequence is a user-defined schema bound object that generates a sequence of numeric values according to the specification with which the sequence was created. The sequence of numeric values is generated in an ascending or descending order at a defined interval and can be configured to restart (cycle) when exhausted.
Sequence Numbers
NEW QUESTION: 2
무역 신용으로 단기 금융을 받는 기업은 다음과 같은 경우에 더 높은 비율의 금융 비용을 지불합니다.
A. 구매 한 품목의 가격이 더 높습니다.
B. 공급 업체는 더 긴 할인 기간을 제공합니다.
C. 구매 한 품목의 가격이 더 낮습니다.
D. 할인 비율이 낮습니다.
Answer: B
Explanation:
If the discount period is longer, the days of extra credit obtained by forgoing the discount are fewer. Assuming other factors are constant, the result is that the cost of trade credit, that is, the cost of not taking the discount, is greater.
NEW QUESTION: 3
A. Option B
B. Option A
Answer: B
NEW QUESTION: 4
VPC 용 인터넷 연결을 설계하고 있습니다. 웹 서버는 인터넷에서 사용할수 있어야 합니다. 응용 프로그램에는 고 가용성 아키텍처가 있어야합니다.
어떤 대안을 고려해야 합니까? 2 답 선택
A. 모든 웹 서버에 EIP를 할당합니다.
상태 검사 및 DNS 장애 조치를 사용하여 모든 EIP로 Route53 레코드 세트를 구성합니다.
B. ELB를 EIP로 구성합니다. ELB 뒤에 모든 웹 서버를 배치하십시오.
EIP를 가리키는 Route53 A 레코드를 구성하십시오.
C. VPC에서 NAT 인스턴스를 구성합니다.
NAT 인스턴스를 통해 기본 경로를 만들고이를 모든 서브넷과 연결하십시오.
NAT 인스턴스 공용 IP 주소를 가리키는 DNS A 레코드를 구성합니다.
D. 모든 웹 서버를 ELB 뒤에 놓습니다.
ELB DNS 이름을 가리 키도록 Route53 CNAME을 구성합니다.
E. CloudFront 배포를 구성하고 웹 서버의 개인 IP 주소를 가리 키도록 원본을 구성합니다.
Route53 CNAME 레코드를 CloudFront 배포판에 구성하십시오.
Answer: A,D
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