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Huawei H19-172_V1.0 - HCSA-Presales-Smart Charging Network V1.0 Exam Braindumps

Huawei H19-172_V1.0 - HCSA-Presales-Smart Charging Network V1.0 Exam Braindumps

  • Certification Provider:Huawei
  • Exam Code:H19-172_V1.0
  • Exam Name:HCSA-Presales-Smart Charging Network V1.0 Exam Exam
  • Total Questions:276 Questions and Answers
  • Product Format: PDF & Test Engine Software Version
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NEW QUESTION: 1
A 24-year-old graduate student recognizes that he has a phobia. He suffers severe anxiety when he is in darkness. It has altered his lifestyle because he is unable to go to a movie theater, concert, and other events that may require absence of light. The client is seeking assistance because he is no longer able to socialize with friends due to his phobia. The psychologist working with him is using desensitization. He has asked the nursing staff to assist the client in muscle relaxation techniques. What result would indicate client education has been successful?
A. He enters a movie theater, sits in his chair, and replaces anxiety with relaxation as the theater darkens.
B. He enters a concert, but as the lights dim, he does not experience anxiety.
C. He takes a part-time job as a photographic assistant. His job necessitates his working in a darkroom.
D. He states that he no longer fears dark places.
Answer: A
Explanation:
Explanation
(A) This situation provides specific evidence that the client is able to integrate muscle relaxation technique into his lifestyle to alleviate anxiety. (B) The client may not experience anxiety at the concert, but there is no evidence regarding the technique that he used to alleviate anxiety. (C) The client may state he no longer experiences anxiety, but there is no evidence demonstrating this. He may be denying anxiety to discontinue therapy prematurely. (D) Does he experience anxiety in the darkroom? He may have taken this job to force himself to deal with the phobia directly.

NEW QUESTION: 2
Which of these is the equation used to derive a 64 Kbps bit rate?
A. 8 kHz x 8-bit code words
B. 2 x 8 kHz x 4-bit code words
C. 2 x 4 kHz x 8-bit code words
D. 2 x 4-bit code words x 8 kHz
Answer: C
Explanation:
While the human ear can sense sounds from 20 to 20, 000 Hz, and speech encompasses sounds
from about 200 to 9000 Hz, the telephone channel was designed to operate at about 300 to 3400
Hz. This economical range carries enough fidelity to allow callers to identify the party at the far end
and sense their mood. Nyquist decided to extend the digitization to 4000 Hz, to capture higher-
frequency sounds that the telephone channel may deliver. Therefore, the highest frequency for
voice is 4000 Hz. According to Nyquist theory, we must double the highest frequency, so 2x4kHz
= 8kHz.
Each sample will be encoded into a 8-bit code. Therefore 8kHz x 8-bit code = 64 Kbps (notice
about the unit Kbps: 8kHz = 8000 samples per second so 8000 x 8-bit = 64000 bit per second =
64 Kilobit per second = 64 Kbps)
Link: http://encyclopedia2.thefreedictionary.com/Nyquist+theorem
Note:
Nyquist theory:
"When sampling a signal (e.g., converting from an analog signal to digital), the sampling frequency
must be greater than twice the bandwidth of the input signal in order to be able to reconstruct the
original perfectly from the sampled version."

NEW QUESTION: 3
EtherChannelを構成するプロセスは何ですか?
A. ポートをシャットダウンする必要はありません
B. ポートがerr-disableの場合、シャットダウンが必要です
C. 片側のみのインターフェースをシャットダウンします
D. 両方のインターフェースポートをシャットダウンします
Answer: D

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