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    NEW QUESTION: 1
    The ip-link principle is to continuously send ICMP packets or ARP request packets to the specified destination address, and check whether the ICMP echo reply or ARP reply packet of the destination IP response can be received.
    A. TRUE
    B. FALSE
    Answer: A

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    B. The file must contain only tabs as white space characters.
    C. Only one selector, facility, level, is allowed per line.
    D. Only one action is allowed per line.
    E. Wildcard characters (*) are NOT allowed.
    Answer: B,D

    NEW QUESTION: 3
    Which two are true about granting privileges on objects?
    A. A table owner must grant the REFERENCES privilege to allow other users to create FOREIGN KEY constraints using that table.
    B. The owner of an object acquires all object privileges on that object by default.
    C. The WITH GRANT OPTION clause can be used only by DBA users.
    D. An object privilege can be granted to a role only by the owner of that object.
    E. An object privilege can be granted to other users only by the owner of that object.
    Answer: A,B

    NEW QUESTION: 4
    The network administrator is asked to configure 113 point-to-point links. Which IP addressing scheme defines the address range and subnet mask that meet the requirement and waste the fewest subnet and host addresses?
    A. 10.10.1.0/24 subnetted with mask 255.255.255.252
    B. 10.10.1.0/25 subnetted with mask 255.255.255.252
    C. 10.10.0.0/16 subnetted with mask 255.255.255.252
    D. 10.10.0.0/18 subnetted with mask 255.255.255.252
    E. 10.10.0.0/23 subnetted with mask 255.255.255.252
    Answer: E
    Explanation:
    Explanation
    We need 113 point-to-point links which equal to 113 sub-networks < 128 so we need to
    borrow 7 bits (because 2

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    7 = 128).
    The network used for point-to-point connection should be /30.
    So our initial network should be 30 - 7 = 23.
    So 10.10.0.0/23 is the correct answer.
    You can understand it more clearly when writing it in binary form:
    /23 = 1111 1111.1111 1110.0000 0000
    /30 = 1111 1111.1111 1111.1111 1100 (borrow 7 bits)
    Topic 4, IP Routing Technologies

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