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ISTQB ISTQB-CTFL - ISTQB-Foundation Level Exam Exam Braindumps

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  • Exam Code:ISTQB-CTFL
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  • Total Questions:276 Questions and Answers
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NEW QUESTION: 1
Which item is a main component of the Symantec Data Center Security: Server Advanced architecture?
A. Oracle database
B. Management server
C. Network access control enforcer
D. Agent web interface
Answer: C

NEW QUESTION: 2
You maintain an application that is used by local food delivery companies. When a customer requests a delivery, the application sends a message to all of the delivery companies. One company accepts the request and fulfills the order.
The application currently supports orders of 100 products or fewer. Some of the delivery companies can now deliver large orders that contain up to 500 products.
You must modify the application so that it supports both small orders and large orders. Messages about large orders should be sent to only delivery companies that can fulfill them. Messages about small orders should be sent to all delivery companies.
Which service should you use?
A. Azure Service Bus Relay
B. Azure Service Bus Topics
C. Azure Service Bus Queue
D. Azure Service Bus Namespace
Answer: B

NEW QUESTION: 3
Refer to the exhibit. The network is converged.
After link-state advertisements are received from Router_A, what information will Router_E contain in its routing table for the subnets 208.149.23.64 and
208.149.23.96?

A. O 208.149.23.64 [110/3] via 190.172.23.10, 00:00:07, Serial 1/0 O 208.149.23.96 [110/3] via 190.172.23.10, 00:00:16, Serial 1/0
B. O 208.149.23.64 [110/1] via 190.172.23.10, 00:00:07, Serial 1/0 O 208.149.23.96 [110/3] via 190.173.23.10, 00:00:16, FastEthernet 0/0
C. O 208.149.23.64 [110/13] via 190.173.23.10, 00:00:07, FastEthernet 0/0 O 208.149.23.96 [110/13] via 190.173.23.10, 00:00:16, FastEthernet 0/0
D. O 208.149.23.64 [110/13] via 190.172.23.10, 00:00:07, Serial 1/0 O 208.149.23.96 [110/13] via 190.172.23.10, 00:00:16, Serial 1/0 O 208.149.23.96 [110/13] via
190.173.23.10, 00:00:16, FastEthernet 0/0
Answer: C
Explanation:
Router_E learns two subnets subnets 208.149.23.64 and 208.149.23.96 via Router_A through FastEthernet interface. The interface cost is calculated with the formula 108 / Bandwidth. For FastEthernet it is 108 / 100 Mbps = 108 / 100,000,000 = 1. Therefore, the cost is 12 (learned from Router_A) + 1 = 13 for both subnets
-B is not correct. The cost through T1 link is much higher than through T3 link (T1 cost = 108 / 1.544 Mbps = 64; T3 cost = 108 / 45 Mbps = 2) so surely OSPF will choose the path through T3 link -> Router_E will choose the path from Router_A through FastEthernet0/0, not Serial1/0 -C & D are not correct.
In fact, we can quickly eliminate answers B, C and D because they contain at least one subnet learned from Serial1/0 -they are surely incorrect.

NEW QUESTION: 4
Why is the same client subnet difficult to load balance across ISGs?
A. Two separate RADIUS accounting sessions must be established as traffic.
B. The ISG requires symmetrical traffic flows, and standard routing cannot determine the return path for client traffic.
C. Each subnet is associated with a control policy, and the policy server cannot process policy events from the same policy on different interfaces.
D. The policy server is unable to identify which ISG the session belongs to.
Answer: B

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