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NEW QUESTION: 1
Ein Product Owner hat dem Team einen priorisierten Rückstand für die erstmalige Einführung eines neuen Produkts zur Verfügung gestellt. Nach der Analyse kommt das Team zu dem Schluss, dass einige Arbeiten zur Unterstützung des ersten Starts fehlen, und stellt diese Informationen dem Product Owner zur Verfügung. Der Product Owner bestätigt die fehlende Arbeit und fügt sie am Ende des Backlogs hinzu. Das Team ist mit der Priorisierung der fehlenden Arbeit nicht zufrieden.
Was soll der Projektmanager in dieser Situation tun?
A. Befähigen Sie den Product Owner, indem Sie die Entscheidung unterstützen und das Team anweisen, die vorgegebene Priorisierung zu befolgen.
B. Empfehlen Sie dem Product Owner, die fehlende Arbeit höher zu priorisieren, da sie für das Minimum Viable Product (MVP) benötigt wird.
C. Lassen Sie das Projektteam die empfohlene Arbeit aus dem unteren Bereich des Backlogs ziehen, um die Wertschöpfung zu maximieren.
D. Analysieren und priorisieren Sie den Rückstand und geben Sie die Entscheidung an den Product Owner und das Team weiter.
Answer: B

NEW QUESTION: 2
An administrator has a backup policy with the following policy attributes:
3 paths listed in the Backup Selections list

5 clients listed in the Clients list

Allow multiple data streams is selected

Limit Jobs per policy is set to 4

How many jobs go Active when the job is started, excluding parents job?
A. 0
B. 1
C. 2
D. 3
Answer: D

NEW QUESTION: 3
What happens when you attempt to compile and run the following code?
#include <deque>
#include <iostream>
#include <algorithm>
using namespace std;
class B { int val;
public:
B(int v):val(v){} B(){}
int getV() const {return val;} };
ostream & operator <<(ostream & out, const B & v) { out<<v.getV(); return out;} template<class T>struct Out { ostream & out; Out(ostream & o): out(o){} void operator() (const T & val ) { out<<val<<" "; } }; int main() { int t[]={8, 10, 5, 1, 4, 6, 2, 7, 9, 3}; deque<B> d1(t, t+10); deque<B>::iterator it = lower_bound(d1.begin(), d1.end(), 4); for_each(it, d1.end(), Out<B>(cout));cout<<endl; return 0;
}
Program outputs:
A. 1 2 3 4
B. 4 5 6 7 8 9 10
C. 8 10 5 1 4 6 2 7 9 3
D. compilation error
E. 1 2 3 4 5 6 7 8 9 10
Answer: D