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NEW QUESTION: 1
Planning Assistanceデータベースを設計する必要があります。
以下の各ステートメントについて、ステートメントが真である場合は「はい」を選択します。それ以外の場合は、「いいえ」を選択します。
注：それぞれの正しい選択には1ポイントの価値があります。
Answer:
Explanation:
Explanation
Box 1: No
Data used for Planning Assistance must be stored in a sharded Azure SQL Database.
Box 2: Yes
Box 3: Yes
Planning Assistance database will include reports tracking the travel of a single vehicle
NEW QUESTION: 2
What monitoring characteristic may indicate the risk of FC switch port failure before the ports actually fails?
A. Security
B. Performance
C. Accessibility
D. Capacity
Answer: B
NEW QUESTION: 3
Which statement about SIP precondition is most correct?
A. RSVP agents are only required for the IP phones. SIP trunks require RSVP agents only when fall back
to local RSVP is configured.
B. When configuring SIP precondition, the IP phones and SIP trunk must have access to an RSVP agent.
C. SIP trunk will always require RSVP agents regardless of what RSVP type is configured.
D. When configuring SIP precondition, the IP phones must have access to an RSVP agent.
E. When configuring SIP precondition, the SIP trunk must have access to an RSVP agent.
Answer: A
NEW QUESTION: 4
You are a database developer for an application hosted on a Microsoft SQL Server 2012 server. The database contains two tables that have the following definitions:
Global customers place orders from several countries. You need to view the country from which each customer has placed the most orders. Which Transact-SQL query do you use?
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN
(SELECT CustomerID, ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY OrderAmount DESC) AS Rnk
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
WHERE o.Rnk = 1
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM (SELECT c.CustomerID, c.CustomerName, o.ShippingCountry, RANK() OVER (PARTITION BY CustomerID
ORDER BY COUNT(o.OrderAmount) ASC) AS Rnk
FROM Customer c
INNER JOIN Orders o
ON c.CustomerID = o.CustomerID
GROUP BY c.CustomerID, c.CustomerName, o.ShippingCountry) cs
WHERE Rnk = 1
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN
(SELECT CustomerID, ShippingCountry,
COUNT(OrderAmount) DESC) AS OrderAmount
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
ORDER BY OrderAmount DESC
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN
(SELECT CustomerID, ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY COUNT(OrderAmount) DESC) AS Rnk
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
WHERE o.Rnk = 1
Answer: D
Explanation:
--Burgos - NO
Verified answer as correct.
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