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NEW QUESTION: 1
In your database instance, the user sessions are connected to the database server from the remote machines. You want to achieve the following for these users:
1 . The user account must be locked after four unsuccessful login attempts.
2 . The user must be prompted to change the password at regular intervals.
3 . The user may not have more than three simultaneous sessions.
4 . The user session must automatically be logged off if more than 10 minutes elapsed time used.
How would you accomplish the above?
A. By implementing the Database Resource Manager plan
B. By granting a secure application role to the users
C. By assigning profiles for the users
D. By implementing Fine-Grained Auditing (FGA)
Answer: C

NEW QUESTION: 2
In a vSphere High Availability (vSphere HA) cluster, which condition can be detected by datastore heartbeating?
A. Fault tolerance virtual machine (VM) failover
B. Virtual machine (VM) disk failure
C. Network isolation
D. Datastore All Paths Down (APD) event
Answer: C
Explanation:
https://docs.vmware.com/en/VMware-vSphere/6.5/vsphere-esxi-vcenter-server-65-availability-guide.pdf (19)

NEW QUESTION: 3
An Organization uses Exchange Online. You enable mailbox audit logging for all mailboxes.
User1 reports that her mailbox has been accessed by someone else.
You need to determine whether someone other than the mailbox owner has accessed the mailbox.
What should you do?
A. In the Exchange Admin Center, navigate to the Auditing section of the Protection page. Run a non-owner mailbox access report.
B. Run the following Windows PowerShell command: Search-MailboxAuditLog-Identity User1-LogonTypes Admin, Delegate, External-ShowDetails
C. In the Exchange Admin Center, navigate to the In-place eDiscovery & Hold section of the Compliance Management page. Run a non-owner mailbox access report.
D. Run the following Windows PowerShell command: New-AdminAuditLogSearch-Identity User1-LogonTypes Admin, Delegate, External-ShowDetails
Answer: C
Explanation:
Explanation
The Non-Owner Mailbox Access Report in the Exchange Administration Center (EAC) lists the mailboxes that have been accessed by someone other than the person who owns the mailbox.
Run a non-owner mailbox access report
Note: When a mailbox is accessed by a non-owner, Microsoft Exchange logs information about this action in a mailbox audit log that's stored as an email message in a hidden folder in the mailbox being audited. Entries from this log are displayed as search results and include a list of mailboxes accessed by a non-owner, who accessed the mailbox and when, the actions performed by the non-owner, and whether the action was successful.
References: https://technet.microsoft.com/en-us/library/jj150575(v=exchg.150).aspx

NEW QUESTION: 4
Which SQL procedure declaration is coded correctly?
A. CREATE PROCEDURE myproc(IN salary DOUBLE, OUT commission DOUBLE)
BEGIN
DECLARE a DOUBLE;
DECLARE my_cur CURSOR FOR SELECT * FROM employee;
DECLARE EXIT HANDLER FOR SQLEXCEPTION
SET commission = 0;
SET a = .06 * salary;
SET commission = a;
END
B. CREATE PROCEDURE myproc(IN salary DOUBLE, OUT commission DOUBLE)
BEGIN
DECLARE EXIT HANDLER FOR SQLEXCEPTION
SET commission = 0;
DECLARE a DOUBLE;
DECLARE my_cur CURSOR FOR SELECT * FROM employee;
SET a = .06 * salary;
SET commission = a;
END
C. CREATE PROCEDURE myproc(IN salary DOUBLE, OUT commission DOUBLE)
BEGIN
DECLARE a DOUBLE;
DECLARE EXIT HANDLER FOR SQLEXCEPTION
SET commission = 0;
DECLARE my_cur CURSOR FOR SELECT * FROM employee;
SET a = .06 * salary;
SET commission = a;
END
D. CREATE PROCEDURE myproc(IN salary DOUBLE, OUT commission DOUBLE)
BEGIN
DECLARE EXIT HANDLER FOR SQLEXCEPTION
SET commission = 0;
DECLARE my_cur CURSOR FOR SELECT * FROM employee;
DECLARE a DOUBLE;
SET a = .06 * salary;
SET commission = a;
END
Answer: A