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Juniper JN0-232 - Security, Associate (JNCIA-SEC) Exam Braindumps

Juniper JN0-232 - Security, Associate (JNCIA-SEC) Exam Braindumps

  • Certification Provider:Juniper
  • Exam Code:JN0-232
  • Exam Name:Security, Associate (JNCIA-SEC) Exam Exam
  • Total Questions:276 Questions and Answers
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NEW QUESTION: 1
以下の各ステートメントについて、そのステートメントが正しい場合は「はい」を選択してください。そうでなければ、いいえを選択します。
注:それぞれ正しい選択は1ポイントの価値があります。

Answer:
Explanation:


NEW QUESTION: 2
あなたはアプリケーションをテストしています。 このアプリケーションには、CalculateInterestおよびLogLineという名前のメソッドが含まれています。 CalculateInterest()メソッドは、ローンの利子を計算します。 LogLine()メソッドは、診断メッセージをコンソールウィンドウに送信します。
次のコードはメソッドを実装しています。 (行番号は参照用にのみ記載されています)。

あなたには次の要件があります。
* CalculateInterest()メソッドは、すべてのビルド構成に対して実行する必要があります。
* LogLine()メソッドは、デバッグビルドでのみ実行する必要があります。
あなたは、方法が正しく動くことを保証する必要がある。
2つのこのゴールを達成することについて可能な方法が何であるか? (それぞれの正解は完全な解答を提示しますが、2つを選択してください)。
A. Insert the following code segment at line 01:
# if DEBUG
Insert the following code segment at line 10:
# endif
B. Insert the following code segment at line 01:
# region DEBUG
Insert the following code segment at line 10:
# endregion
C. Insert the following code segment at line 01:
[Conditional("DEBUG")]
D. Insert the following code segment at line 10:
[Conditional("DEBUG")]
E. Insert the following code segment at line 05:
# region DEBUG
Insert the following code segment at line 07:
# endregion
F. Insert the following code segment at line 10:
[Conditional("RELEASE")]
G. Insert the following code segment at line 05:
# if DEBUG
Insert the following code segment at line 07:
# endif
Answer: D,G
Explanation:
Explanation
D: Also, it's worth pointing out that you can use [Conditional("DEBUG")] attribute on methods that return void to have them only executed if a certain symbol is defined. The compiler would remove all calls to those methods if the symbol is not defined:
[Conditional("DEBUG")]
void PrintLog() {
Console.WriteLine("Debug info");
}
void Test() {
PrintLog();
}
G: When the C# compiler encounters an directive, followed eventually by an #endif directive, it will compile the code between the directives only if the specified symbol is defined. Unlike C and C++, you cannot assign a numeric value to a symbol; the #if statement in C# is Boolean and only tests whether the symbol has been defined or not. For example,
#define DEBUG
#if DEBUG
Console.WriteLine("Debug version");
#endif
Reference: http://stackoverflow.com/questions/2104099/c-sharp-if-then-directives-for-debug-vs-release

NEW QUESTION: 3
インスタンスは、インスタンスの起動中に作成されたプライマリVNICで起動されます。
セカンダリVNICを既存のインスタンスに追加するときに当てはまる操作はどれですか。 (2つ選択してください。)
A. 必要がなければ、後でセカンダリVNICを削除できます。
B. 2つのVNICをインスタンスに接続することはできません。
C. プライマリVNICとセカンダリVNICの関連付けは、同じ可用性ドメイン内にある必要があります。
D. セカンダリVNICの接続が完了した後、プライマリVNICを削除できます。
Answer: A,C
Explanation:
https://docs.cloud.oracle.com/iaas/Content/Network/Tasks/managingVNICs.htm

NEW QUESTION: 4
You plan to use a Deep Learning Virtual Machine (DLVM) to train deep learning models using Compute Unified Device Architecture (CUDA) computations.
You need to configure the DLVM to support CUDA.
What should you implement?
A. Solid State Drives (SSD)
B. Computer Processing Unit (CPU) speed increase by using overcloking
C. Graphic Processing Unit (GPU)
D. Intel Software Guard Extensions (Intel SGX) technology
E. High Random Access Memory (RAM) configuration
Answer: C
Explanation:
A Deep Learning Virtual Machine is a pre-configured environment for deep learning using GPU instances.
References:
https://azuremarketplace.microsoft.com/en-au/marketplace/apps/microsoft-ads.dsvm-deep-learning

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