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NEW QUESTION: 1
Which of the following is a visual decomposition of the program scope and the resources needed in order to create the things defined within the program scope?
A. Budgeted Cost of Work Scheduled (BCWS)
B. Resource breakdown structure (RBS)
C. product breakdown structure (PBS)
D. Work Breakdown Structure (WBS)
Answer: B
NEW QUESTION: 2
Click the Exhibit button.
You have configured a BGP-signaled Layer 2 VPN with the configuration shown in the exhibit.
Which two statements are true in this situation? (Choose two.)
A. The route-distinguisher is in the wrong format.
B. The local site is site ID 1.
C. Interface ge-0/0/l.512 is connected to the local site
D. Remote site 1 is dual-homed.
Answer: B,D
Explanation:
Explanation/Reference:
Reference: https://www.juniper.net/documentation/en_US/junos/topics/usage-guidelines/vpns-configuring- routing-instances-on-pe-routers-in-vpns.html#id-10110155
NEW QUESTION: 3
You are a database developer for an application hosted on a Microsoft SQL Server 2012 server.
The database contains two tables that have the following definitions:
Global customers place orders from several countries.
You need to view the country from which each customer has placed the most orders.
Which Transact-SQL query do you use?
A. ShippingCountry) cs
WHERE Rnk = 1
B. SELECT CustomerID, CustomerName, ShippingCountry
FROM
(SELECT c.CustomerID, c.CustomerName,
C. ShippingCountry) cs
WHERE Rnk = 1
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM Customer c
INNER JOIN
(SELECT CustomerID, ShippingCountry,
COUNT(OrderAmount) AS OrderAmount
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
ORDER BY OrderAmount DESC
E. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM Customer c
INNER JOIN
(SELECT CustomerID, ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY COUNT(OrderAmount) DESC) AS Rnk
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
Where o.Rnk = 1
F. ShippingCountry,
RANK() OVER (PARTITION BY c. CustomerID
ORDER BY o. OrderAmount DESC) AS Rnk
FROM Customer c
INNER JOIN Orders o
ON c.CustomerID = o.CustomerID
GROUP BY c.CustomerID, c.CustomerName,
G. SELECT CustomerID, CustomerName, ShippingCountry
FROM
(SELECT c.CustomerID, c.CustomerName, o.ShippingCountry,
RANK() OVER (PARTITION BY c.CustomerID
ORDER BY COUNT(o.OrderAmount) ASC) AS Rnk
FROM Customer c
INNER JOIN Orders o
ON c.CustomerID = o.CustomerID
GROUP BY c.CustomerID, c.CustomerName,
Answer: D
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