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Fortinet FCSS_SDW_AR-7.4 - FCSS - SD-WAN 7.4 Architect Exam Braindumps

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  • Certification Provider:Fortinet
  • Exam Code:FCSS_SDW_AR-7.4
  • Exam Name:FCSS - SD-WAN 7.4 Architect Exam Exam
  • Total Questions:276 Questions and Answers
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NEW QUESTION: 1
You run the Get-SendConnector cmdlet and you receive the following output.


You need to recommend which actions are required to secure email connectivity between the contoso.com SMTP domain and the fabrikam.com SMTP domain.
Which two actions should you recommend? Each correct answer presents part of the solution.
A. Configure theTLSSendDomainSecureListparameXer for the organization.
B. Create an Outlook protection rule.
C. Import a server certificate that has a subject name of smtp.contoso.com.
D. Modify theConnecforTypeparameter for the Send connector.
E. Import a server certificate that has a subject name ofex01.contoso.com and a subject alternate name ofex02.contoso.com.
Answer: A,C
Explanation:
Explanation
References:
https://technet.microsoft.com/en-gb/library/bb123543(v=exchg.141 ).aspx

NEW QUESTION: 2
Sie sind Datenbankentwickler für eine Anwendung, die auf einem Microsoft SQL Server 2014-Server gehostet wird. Die Datenbank enthält zwei Tabellen mit folgenden Definitionen:

Weltweite Kunden bestellen aus mehreren Ländern. Sie müssen das Land anzeigen, aus dem jeder Kunde die meisten Bestellungen aufgegeben hat.
Welche Transact-SQL-Abfrage verwenden Sie?
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM (SELECT c.CustomerID, c.CustomerName, o.ShippingCountry, RANK () OVER (PARTITION BY CustomerIDORDER BY COUNT (o.OrderAmount) ASC) AS RnkFROM Kunden-CINNER JOIN Bestellungen oON c.CustomerID = o.CustomerIDGROUP BY c.CustomerID, c.CustomerName, o.ShippingCountry) cs WHERE Rnk = 1
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer CINNER JOIN (SELECT customerID, ShippingCountry, RANK () OVER (PARTITION NACH CustomerIDORDER NACH OrderAmount DESC) AS RNKFROM OrdersGROUP NACH CustomerID, ShippingCountry) ASOON CustomerID = o.CustomerIDWHERE o.Rnk = 1
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer CINNER JOIN (SELECT CustomerID, Versandland, RANK () OVER (PARTITION NACH CustomerIDORDER NACH COUNT (OrderAmount) DESC) AS RnkFROM OrdersGROUP BY CustomerID, Versandland) AS oON c.CustomerID = o.CustomerIDWHERE o.Rnk = 1
D. Wählen Sie c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer CINNER aus OrderAmount DESC
Answer: C
Explanation:
Erläuterung
Verwenden Sie die absteigende Reihenfolge (DESC).
Um nach der Anzahl der Bestellungen zu bestellen, verwenden wir ORDER BY COUNT (OrderAmount).
Schließlich wird ein WHERE-Abschluss benötigt: WHERE o.Rnk = 1

NEW QUESTION: 3

A. Option B
B. Option D
C. Option C
D. Option A
Answer: D

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