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NEW QUESTION: 1
Which of the following is the most reliable method to estimate the effectiveness of standard procedures to minimize the risk ofcross-contamination during spirometry testing in a pulmonary function laboratory?
A. Observe the handwashing behavior of each technologist.
B. Ask patients tested about laboratory hygiene.
C. Count the number of disposable mouthpieces used for 1 week.
D. Ask technologists if they wash their hands before each test
Answer: A
NEW QUESTION: 2
How can you configure VCS Expressway to make sure an external caller cannot reach a specific internal address?
A. You add the specific URI in the firewall section of the VCS Expressway and block it.
B. You block the call with search rule that has a high priority in the VCS Expressway.
You make a transform on the VCS Expressway to direct the call to VCS Control, which can block the call.
C. VCS Expressway only forwards calls to Cisco Unified Communications Manager who block calls.
D. You add a search rule to block any call to the specific URI on the internal VCS Control.
Answer: C
NEW QUESTION: 3
You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year marks for students. The table has marks obtained by 50 students for various subjects. You need to ensure that the top half of the students arranged by their average marks must be given a rank of 1 and the remaining students must be given a rank of 2. Which Transact-SQL query should you use?
A. SELECT StudentCode as Code,
NTILE (2) OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
B. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER (PARTITION BY SubjectCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
C. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER (PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
D. SELECT StudentCode as Code,
DENSE_RANK() OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
E. SELECT Id, Name, Marks,
DENSE_RANK() OVER (ORDER BY Marks DESC) AS Rank
FROM StudentMarks
F. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
G. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
H. SELECT StudentCode as Code,
RANK() OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
Answer: A
Explanation:
--Burgos - NO
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