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Fortinet FCSS_ADA_AR-6.7 - FCSS—Advanced Analytics 6.7 Architect Exam Braindumps

Fortinet FCSS_ADA_AR-6.7 - FCSS—Advanced Analytics 6.7 Architect Exam Braindumps

  • Certification Provider:Fortinet
  • Exam Code:FCSS_ADA_AR-6.7
  • Exam Name:FCSS—Advanced Analytics 6.7 Architect Exam Exam
  • Total Questions:276 Questions and Answers
  • Product Format: PDF & Test Engine Software Version
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NEW QUESTION: 1

A. Option D
B. Option A
C. Option B
D. Option C
Answer: D
Explanation:
Explanation
References:
http://docs.oracle.com/cd/B19306_01/server.102/b14231/undo.htm
(undo retention, see the bullets)

NEW QUESTION: 2
You work as a Software Developer for ABC Inc. You create a Console application named
ConsoleApplication4. You use the System.Security.Cryptography namespace. You want to use the key lengths of 384 bits to 16384 bits. You use RSACryptoServiceProvider class to encrypt and decrypt data. Which of the following code segments will you use to accomplish this task?
Each correct answer represents a part of the solution. Choose all that apply.
A. UnicodeEncoding ByteConverter = new UnicodeEncoding();
byte[] DataToEncrypt = ByteConverter.GetBytes("Encrypt this line for testing");
byte[] encryptData;
byte[] decryptData;
RSACryptoServiceProvider RSA = new RSACryptoServiceProvider();
encryptData = RSA.Encrypt(DataToEncrypt, false);
Console.WriteLine("Encrypted : {0}", ByteConverter.GetString(encryptData));
decryptData = RSA.Decrypt(encryptData,true);
Console.WriteLine("Decrypted : {0}", ByteConverter.GetString(decryptData));
B. UnicodeEncoding ByteConverter = new UnicodeEncoding();
byte[] DataToEncrypt = ByteConverter.GetBytes("Encrypt this line for testing");
byte[] encryptData;
byte[] decryptData;
RSACryptoServiceProvider RSA = new RSACryptoServiceProvider();
encryptData = RSA.Encrypt(DataToEncrypt, true);
Console.WriteLine("Encrypted : {0}", ByteConverter.GetString(encryptData));
decryptData = RSA.Decrypt(encryptData,true);
Console.WriteLine("Decrypted : {0}", ByteConverter.GetString(decryptData));
C. UnicodeEncoding ByteConverter = new UnicodeEncoding();
byte[] DataToEncrypt = ByteConverter.GetBytes("Encrypt this line for testing");
byte[] encryptData;
byte[] decryptData;
RSACryptoServiceProvider RSA = new RSACryptoServiceProvider();
encryptData = RSA.Encrypt(DataToEncrypt, true);
Console.WriteLine("Encrypted : {0}", ByteConverter.GetString(encryptData));
decryptData = RSA.Decrypt(encryptData,false);
Console.WriteLine("Decrypted : {0}", ByteConverter.GetString(decryptData));
D. UnicodeEncoding ByteConverter = new UnicodeEncoding();
byte[] DataToEncrypt = ByteConverter.GetBytes("Encrypt this line for testing");
byte[] encryptData;
byte[] decryptData;
RSACryptoServiceProvider RSA = new RSACryptoServiceProvider();
encryptData = RSA.Encrypt(DataToEncrypt, false);
Console.WriteLine("Encrypted : {0}", ByteConverter.GetString(encryptData)); decryptData = RSA.Decrypt(encryptData,false); Console.WriteLine("Decrypted : {0}", ByteConverter.GetString(decryptData));
Answer: B,D

NEW QUESTION: 3
Which statement regarding the Multi-tenant cluster pricing tier is the most correct?
A. Data volume is measured in GBs per month: users are charged at the end of every monthly billing cycle according to the amount of data volume processed and the number of API requests made, no matter the usage amount.
B. Data volume is measured in GBs per month: users accrue charges according to the number of API calls made, but if this monthly total is under $5.00 USD the user will not be charged.
C. Data volume is measured in GBs per month: users pay a flat rate of S500 USD per month for access to the multi-tenant tier and can perform an unlimited number of API calls.
Answer: A

NEW QUESTION: 4
Mary Hames has bought a long FRAwith a notional principal of $10 million. The agreement expires in 30 days, and is based on 90-day LIBOR. The FRA is based upon an initial rate of 4.75%. Assume that at expiration, 90-day LIBOR is 5.5%, and 60-day LIBOR is 5.25%. Calculate the payoff at expiration.
A. $19,008 paid to Hames.
B. $12,338 paid to Hames.
C. $18,496 paid to Hames.
Answer: C

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