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NEW QUESTION: 1
Which of the following is NOT a step within the risk management procedure?
A. Plan
B. Propose
C. Assess
D. Communicate
Answer: B
NEW QUESTION: 2
Given the fragment from Java EE deployment descriptor:
341.
<error-page>
342.
<exception-type>java.lang.Throwable</exception-type>
343.
<location>/mainError.jsp</location>
344.
</error-page>
345.
<error-page>
346.
<exception-type>java.lang.ClassCastException</exception-type>
347.
<location>/castError.jsp</location>
348.
</error-page>
If the web application associated with the fragment above throws a ClassCastException.
Which statement is true?
A. The container invokes castError.jsp
B. The deployment descriptor is invalid.
C. The container invokes mainError.jsp
D. Neither mainError.jsp nor castError.jsp is invoked.
Answer: A
NEW QUESTION: 3
Which statement about the feasibility condition in EIGRP is true?
A. The EIGRP peer that advertises the prefix to the router has multiple paths to the destination.
B. The EIGRP peer that advertises the prefix to the router is closer to the destination than the router.
C. The EIGRP peer that advertises the prefix cannot be used as a next hop to reach the destination.
D. The prefix is reachable via an EIGRP peer that is in the routing domain of the router.
Answer: B
Explanation:
The advertised metric from an EIGRP neighbor (peer) to the local router is called Advertised Distance (or reported
distance) while the metric from the local router to that network is called Feasible Distance. For example, R1 advertises
network 10.10.10.0/24 with a metric of 20 to R2. For R2, this is the advertised distance. R2 calculates the feasible
distance by adding the metric from the advertised router (R1) to itself. So in this case the feasible distance to network
10.10.10.0/24 is 20 + 50 = 70.
Before a router can be considered a feasible successor, it must pass the feasibility condition rule. In short, the
feasibility condition says that if we learn about a prefix from a neighbor, the advertised distance from that neighbor to
the destination must be lower than our feasible distance to that same destination.
Therefore we see the Advertised Distance always smaller than the Feasible Distance to satisfy the feasibility condition.
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