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NEW QUESTION: 1
Which HPE solution utilizes LT0 tapes?
A. HPE Store0nce 5500
B. HPE Store0nce VSA
C. HPE StoreEver
D. HPE StoreEasy 1840
Answer: C
Explanation:
NEW QUESTION: 2
Which of the following test types are non-functional tests?
I) Acceptance test
II) Regression test
III) Stress test
IV) Component test
V) Reliability test
A. II. Ill and V
B. III and V
C. I.II and IV
D. I, III and V
Answer: C
NEW QUESTION: 3
A user has created a VPC with CIDR 20.0.0.0/16 using the wizard. The user has created a public subnet CIDR (20.0.0.0/24) and VPN only subnets CIDR (20.0.1.0/24) along with the VPN gateway (vgw-12345) to connect to the user's data center. The user's data center has CIDR 172.28.0.0/12. The user has also setup a NAT instance (i-123456) to allow traffic to the internet from the VPN subnet. Which of the below mentioned options is not a valid entry for the main route table in this scenario?
A. Destination: 20.0.1.0/24 and Target: i-12345
B. Destination: 20.0.0.0/16 and Target: local
C. Destination: 172.28.0.0/12 and Target: vgw-12345
D. Destination: 0.0.0.0/0 and Target: i-12345
Answer: A
Explanation:
Explanation
The user can create subnets as per the requirement within a VPC. If the user wants to connect VPC from his own data center, he can setup a public and VPN only subnet which uses hardware VPN access to connect with his data center. When the user has configured this setup with Wizard, it will create a virtual private gateway to route all traffic of the VPN subnet. If the user has setup a NAT instance to route all the Internet requests, then all requests to the internet should be routed to it. All requests to the organization's DC will be routed to the VPN gateway.
Here are the valid entries for the main route table in this scenario:
Destination: 0.0.0.0/0 & Target: i-12345 (To route all internet traffic to the NAT Instance.
Destination: 172.28.0.0/12 & Target: vgw-12345 (To route all the organization's data center traffic to the VPN gateway).
Destination: 20.0.0.0/16 & Target: local (To allow local routing in VPC).
NEW QUESTION: 4
Refer to the exhibit.
The network is converged.After link-state advertisements are received from Router_A, what information will Router_E contain in its routing table for the subnets 208.149.23.64 and 208.149.23.96?
A. 208.149.23.64[110/13] via 190.173.23.10, 00:00:07, FastEthemet0/0 208.149.23.96[110/13] via
190.173.23.10, 00:00:16, FastEthemet0/0
B. 208.149.23.64[110/13] via 190.173.23.10, 00:00:07, Serial1/0 208.149.23.96[110/13] via
190.173.23.10, 00:00:16, Serial1/0 208.149.23.96[110/13] via 190.173.23.10, 00:00:16, FastEthemet0/0
C. 208.149.23.64[110/3] via 190.172.23.10, 00:00:07, Serial1/0 208.149.23.96[110/3] via 190.173.23.10,
00:00:16, Serial1/0
D. 208.149.23.64[110/1] via 190.172.23.10, 00:00:07, Serial1/0 208.149.23.96[110/3] via 190.173.23.10,
00:00:16, FastEthemet0/0
Answer: A
Explanation:
Explanation/Reference:
Router_E learns two subnets subnets 208.149.23.64 and 208.149.23.96 via Router_A through FastEthernet interface. The interface cost is calculated with the formula 108 / Bandwidth. For FastEthernet it is 108 / 100 Mbps = 108 / 100,000,000 = 1. Therefore the cost is 12 (learned from Router_A) + 1 = 13 for both subnets -> The cost through T1 link is much higher than through T3 link (T1 cost = 108 / 1.544 Mbps = 64; T3 cost
108 / 45 Mbps = 2) so surely OSPF will choose the path through T3 link -> Router_E will choose the path from Router_A through FastEthernet0/0, not Serial1/0. In fact, we can quickly eliminate answers B, C and D because they contain at least one subnet learned from Serial1/0 -> they are surely incorrect.
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