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NEW QUESTION: 1
NTPは、どのネットワークデバイスを認証しますか？
A. 唯一のタイムソース
B. ファイアウォールクライアント装置
C. クライアントデバイスと時刻源
D. 唯一のクライアントデバイス
Answer: A
Explanation:
Explanation
You can configure the device to authenticate the time sources to which the local clock is synchronized. When
you enable NTP authentication, the device synchronizes to a time source only if the source carries one of the
authentication keys specified by the ntp trusted-key command. The device drops any packets that fail the
authentication check and prevents them from updating the local clock. NTP authentication is disabled by
default.
Source:
http://www.cisco.com/c/en/us/td/docs/switches/datacenter/sw/5_x/nx-os/system_management/
configuration/guide/sm_nx_os_cg/sm_3ntp.html#wp1100303%0A
NEW QUESTION: 2
Which of the following statements are correct regarding MAC address of VRRP packet?
(Choose two.)
A. The destination MAC is multicast MAC address.
B. The source address is physical MAC address of Master.
C. The destination MAC is broadcast MAC address.
D. The source address is virtual MAC address.
Answer: A,D
NEW QUESTION: 3
Your client upgraded their Voice Portal to an Avaya Aura Experience Portal (AAEP) and upgraded Avaya Proactive Outreach Manager (POM) software. Now their POMDriverApp application which is located on a separate application server is not working.
What would be causing this problem?
A. There are no Announcement Port licenses available for the POMDriverApp.
B. The new POMDriverApp provided with the POM software was not deployed on the application server.
C. A remote database was not configured on the AAEP.
D. The user has incorrect roles assigned.
Answer: D
NEW QUESTION: 4
CORRECT TEXT
Problem Scenario 57 : You have been given below code snippet.
val a = sc.parallelize(1 to 9, 3) operationl
Write a correct code snippet for operationl which will produce desired output, shown below.
Array[(String, Seq[lnt])] = Array((even,ArrayBuffer(2, 4, G, 8)), (odd,ArrayBuffer(1, 3, 5, 7,
9)))
Answer:
Explanation:
See the explanation for Step by Step Solution and configuration.
Explanation:
Solution :
a.groupBy(x => {if (x % 2 == 0) "even" else "odd" }).collect
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