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NEW QUESTION: 1
You are the Exchange Administrator for the ABC Corporation's Exchange 2010 organization. People from outside your organization make inquiries to ABC's Tax department.
You create a Tax distribution group that contains all members of the Tax department so people can send questions to the members of the department.
You have a number of additional requirements:
A user named George must be able to review and approve all messages sent to the Tax distribution group.
When George sends a message to the distribution group it should be delivered immediately, without his approval being required.
What should you do? (Choose all that apply).
A. Add George's account as a sender that does not require message approval.
B. Check Messages sent to this group have to be approved by a moderator on the properties page of the Tax distribution group.
C. Check Notify senders in your organization only when their messages aren't approved.
D. Add George's account as group moderator of the Tax distribution group.
E. Remove George's account from the Tax distribution group, add him to another distribution group, and add that group as a member of the Tax distribution group.
Answer: A,B,D
NEW QUESTION: 2
A. Option A
B. Option D
C. Option C
D. Option B
Answer: C
NEW QUESTION: 3
Examine the structure of the EMPLOYEES table.
NameNull?Type
---------------------- ------------
EMPLOYEE_IDNOT NULLNUMBER(6)
FIRST_NAMEVARCHAR2(20)
LAST_NAMENOT NULLVARCHAR2(25)
EMAILNOT NULLVARCHAR2(25)
PHONE NUMBERVARCHAR2(20)
HIRE_DATENOT NULLDATE
JOB_IDNOT NULLVARCHAR2(10)
SALARYNUMBER(8,2)
COMMISSION_PCTNUMBER(2,2)
MANAGER_IDNUMBER(6)
DEPARTMENT_IDNUMBER(4)
There is a parent/child relationship between EMPLOYEE_ID and MANAGER_ID.
You want to display the last names and manager IDs of employees who work for the same manager as the employee whose EMPLOYEE_ID is 123.
Which query provides the correct output?
A. SELECT m.last_name, e.manager_idFROM employees e LEFT OUTER JOIN
employees mon (e.manager_id = m.manager_id)WHERE e.employee_id = 123;
B. SELECT e.last_name, e.manager_idFROM employees e RIGHT OUTER JOIN
employees mon (e.employee_id = m.employee_id)WHERE e.employee_id = 123;
C. SELECT e.last_name, m.manager_idFROM employees e RIGHT OUTER JOIN
employees mon (e.employee_id = m.manager_id)WHERE e.employee_id = 123;
D. SELECT e.last_name, m.manager_idFROM employees e RIGHT OUTER JOIN
employees mon (e.manager_id = m.employee_id)AND e.employee_id = 123;
Answer: C
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