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Salesforce CRM-Analytics-and-Einstein-Discovery-Consultant - Salesforce Certified CRM Analytics and Einstein Discovery Consultant Exam Braindumps

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  • Certification Provider:Salesforce
  • Exam Code:CRM-Analytics-and-Einstein-Discovery-Consultant
  • Exam Name:Salesforce Certified CRM Analytics and Einstein Discovery Consultant Exam Exam
  • Total Questions:276 Questions and Answers
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NEW QUESTION: 1
Sie haben einen Hyper-V-Host namens Server1, auf dem Windows Server 2016 ausgeführt wird. Server1 stellt eine Verbindung zu Ihrem Unternehmensnetzwerk her. Das Unternehmensnetzwerk verwendet den Adressraum 10.10.0.0/16.
Server1 hostet eine virtuelle Maschine mit dem Namen VM1. VM1 ist mit einer IP-Adresse von 172.16.1.54/16 konfiguriert.
Sie müssen sicherstellen, dass VM1 auf die Ressourcen im Unternehmensnetzwerk zugreifen kann.
Was tun? Wählen Sie zum Beantworten die entsprechenden Optionen im Antwortbereich aus.

Answer:
Explanation:



NEW QUESTION: 2
You have a Hyper-V host named Server1 that runs Windows Server 2012 R2. Server1 hosts 50 virtual machines that run Windows Server 2012 R2. Your company uses smart cards for authentication.
You need to ensure that you can use smart card authentication when you connect to the virtual machine by using Virtual Machine Connection. What should you configure?
A. The NUMA Spanning settings
B. The Enhanced Session Mode Policy
C. The remoteFX settings
D. The Integration Services settings
Answer: B
Explanation:
Explanation/Reference:
Explanation:

NEW QUESTION: 3
Which of the following description is wrong about LTE neighbourhood plans?
A. For dense urban areas and ordinary urban areas, because the station spacing is relatively close (0.3~1.0 km), the neighboring area should do more
B. Directly adjacent cells in geographical location in order to be neighbors
C. ANR function can completely replace the neighboring area planning of the initial network
D. Because there is no sequence problem in the neighboring area of LTE, and the detection period is very short, it is only necessary to consider not missing the neighboring area, and it is not necessary to sort the neighboring cells strictly according to the signal strength.
Answer: C

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