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Adobe AD0-E560 - Adobe Marketo Engage Architect Master Exam Braindumps

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  • Certification Provider:Adobe
  • Exam Code:AD0-E560
  • Exam Name:Adobe Marketo Engage Architect Master Exam Exam
  • Total Questions:276 Questions and Answers
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NEW QUESTION: 1
管理者はArubaOSスイッチおよびモビリティコントローラ(MC)が含まれているネットワークをサポートします。
制限的なMCファイアウォールポリシーは、無線アクセスを制御します。 管理者は、イーサネットスイッチポートに接続されているユーザに同じMCファイアウォールポリシーを適用する機能を実装したいと考えています。
どの機能がこの機能を提供しますか?
A. ポートセキュリティ
B. トンネルノード
C. IPSecサイト間トンネリング
D. VSF
Answer: A

NEW QUESTION: 2
Howmany elements will the list2 list contain after execution of the following snippet?
List1= [False fori in range(1,10)] list2 = list1[-1:1:-1]
A. three
B. five
C. seven
D. zero
Answer: C

NEW QUESTION: 3
以下の各ステートメントについて、そのステートメントが正しい場合は「はい」を選択してください。そうでなければ、いいえを選択します。
注:それぞれ正しい選択は1ポイントの価値があります。

Answer:
Explanation:

Explanation
Box 1: Yes
An Azure free account has a spending limit. This is currently 200 USD or 150 GBP.
Box 2: No
Azure free account has a 5 GB blob storage limit and a 5 GB file storage limit.
Box 3: No
Azure free account has a limit of 10 web, mobile or API apps
References:
https://azure.microsoft.com/en-us/free/
https://azure.microsoft.com/en-us/free/free-account-faq/
https://docs.microsoft.com/en-us/azure/billing/billing-avoid-charges-free-account
https://azure.microsoft.com/en-us/free/free-account-faq/
https://docs.microsoft.com/en-us/azure/billing/billing-avoid-charges-free-account

NEW QUESTION: 4
You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year marks for students. The table has marks obtained by 50 students for various subjects.
You need to ensure that the following requirements are met:
* Students must be ranked based on their average marks.
* If one or more students have the same average, the same rank must be given to these students.
* Consecutive ranks must be skipped when the same rank is assigned.
Which Transact-SQL query should you use?
A. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
B. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
C. SELECT StudentCode as Code,
RANK() OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
D. SELECT StudentCode as Code,
DENSE_RANK() OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
E. SELECT Id, Name, Marks,
DENSE_RANK() OVER(ORDER BY Marks DESC) AS Rank
FROM StudentMarks
F. SELECT StudentCode as Code,
NTILE(2) OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
G. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANXO OVER(PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
H. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
Answer: C
Explanation:
Reference: http://msdn.microsoft.com/en-us/library/ms189798.aspx

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