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Huawei H20-713_V1.0 - HCSA-Field-Data Center Facility V1.0 Exam Braindumps

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  • Certification Provider:Huawei
  • Exam Code:H20-713_V1.0
  • Exam Name:HCSA-Field-Data Center Facility V1.0 Exam Exam
  • Total Questions:276 Questions and Answers
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NEW QUESTION: 1
展示を参照してください。

ネットワーク管理者は、ネットワーク内のルーターをリモート管理するためにSSHアクセスを許可する必要があります。運用チームは10.20.1.0/25ネットワーク上にあります。どのコマンドがこのタスクを実行しますか?
A. access-list 2699 permit udp 10.20.1.0 0.0.0.255
B. アクセスリストなし2699はtcpを拒否します10.20.1.0 0.0.0.127 eq 22
C. アクセスリストなし2699 deny ip any 10.20.1.0 0.0.0.255
D. access-list 2699 permit tcp any 10.20.1.0 0.0.0.255 eq 22
Answer: C
Explanation:
Note : Already a statement is there in last to allow SSH Traffic for network 10.20.1.0 0.0.0.127, but Second statement says deny ip any 10.20.1.0 0.0.0.255, so how it will work once it is denied. So the right answer is remove the --- no access-list 2699 deny ip any 10.20.1.0 0.0.0.255.

NEW QUESTION: 2
あなたの会社は、VM1という名前のAzure仮想マシンにデプロイされるWebサービスを開発しています。 Webサービスにより、APIはVM1からリアルタイムデータにアクセスできます。
現在の仮想マシンの展開は、展開の展示に示されています。 ([展開]タブをクリックします)。
最高技術責任者(CTO)から次の電子メールメッセージが送信されます。「開発者はWebサービスをVM1という名前の仮想マシンにデプロイしました。テストの結果、APIはVM1とVM2からアクセスできることがわかりました。パートナーはに接続できる必要があります。インターネットを介したAPI。パートナーは、開発するアプリケーションでこのデータを使用します。」 Azure API Management(APIM)サービスをデプロイします。関連するAPI管理構成は、API展示に示されています。 ([API]タブをクリックします。)次の各ステートメントで、ステートメントがtrueの場合は[はい]を選択します。それ以外の場合は、[いいえ]を選択します。
注:正しい選択はそれぞれ1ポイントの価値があります。

Answer:
Explanation:

Explanation

Reference:
https://docs.microsoft.com/en-us/azure/api-management/api-management-using-with-vnet

NEW QUESTION: 3
Which of the following cryptography demands less computational power and offers more security per bit?
A. Quantum cryptography
B. Symmetric Key Cryptography
C. Elliptic Curve Cryptography (ECC)
D. Asymmetric Key Cryptography
Answer: C
Explanation:
Explanation/Reference:
ECC demands less computational power and, therefore offers more security per bit. For example, an ECC with a 160-bit key offer the same security as an RSA based system with a 1024-bit key.
ECC is a variant and more efficient form of a public key cryptography (how tom manage more security out of minimum resources) gaining prominence is the ECC. ECC works well on a network computer requires strong cryptography but have some limitation such as bandwidth and processing power. This is even more important with devices such as smart cards, wireless phones and other mobile devices.
The following were incorrect answers:
Quantum Cryptography - Quantum cryptography is based on a practical application of the characteristics of the smallest "grain" of light, photons and on physical laws governing their generation, propagation and detection. Quantum cryptography is the next generation of cryptography that may solve some of the existing problem associated with current cryptographic systems, specifically the random generation and secure distribution of symmetric cryptographic keys. Initial commercial usage has already started now that the laboratory research phase has been completed.
Symmetric Encryption - Symmetric encryption is the oldest and best-known technique. A secret key, which can be a number, a word, or just a string of random letters, is applied to the text of a message to change the content in a particular way. This might be as simple as shifting each letter by a number of places in the alphabet. As long as both sender and recipient know the secret key, they can encrypt and decrypt all messages that use this key.
Asymmetric Encryption - The problem with secret keys is exchanging them over the Internet or a large network while preventing them from falling into the wrong hands. Anyone who knows the secret key can decrypt the message. One answer is asymmetric encryption, in which there are two related keys--a key pair. A public key is made freely available to anyone who might want to send you a message. A second, private key is kept secret, so that only you know it. Any message (text, binary files, or documents) that are encrypted by using the public key can only be decrypted by applying the same algorithm, but by using the matching private key. Any message that is encrypted by using the private key can only be decrypted by using the matching public key. This means that you do not have to worry about passing public keys over the Internet (the keys are supposed to be public). A problem with asymmetric encryption, however, is that it is slower than symmetric encryption. It requires far more processing power to both encrypt and decrypt the content of the message.
The following reference(s) were/was used to create this question:
CISA review manual 2014 Page number 349 and 350
http://support.microsoft.com/kb/246071

NEW QUESTION: 4

A. Option B
B. Option A
Answer: A
Explanation:
In an active volume SnapMirror relationship, the size of the source and destination file systems is identical.
However, the size of the destination volume can be larger than or equal to the size of the source volume. Thesize of the file systems must be identical to allow the source to be restored from the destination.
https://library.netapp.com/ecmdocs/ECMP1196991/html/GUID-DE5EE692-81CF-4569-A70300B4E283CE99.html

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