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NEW QUESTION: 1
A. Option D
B. Option A
C. Option B
D. Option C
Answer: B
Explanation:
I suppose this could be an explanation. Not 100% confident about this. The explanation refers to an interface, but the question doesn't specify that.
See the following information for how a packet matches class maps in a policy map for a given interface:
1. A packet can match only one class map in the policy map for each feature type.
2. When the packet matches a class map for a feature type, the ASA does not attempt to match it to any subsequent class maps for that feature type.
3. If the packet matches a subsequent class map for a different feature type, however, then the ASA also applies the actions for the subsequent class map, if supported. See the
"Incompatibility of Certain Feature Actions" section for more information about unsupported combinations.
If a packet matches a class map for connection limits, and also matches a class map for an application inspection, then both actions are applied.
If a packet matches a class map for HTTP inspection, but also matches another class map that includes HTTP inspection, then the second class map actions are not applied.
Source:
http://www.cisco.com/c/en/us/td/docs/security/asa/asa84/configuration/guide/asa_84_cli_co nfig/ mpf_service_policy.html
NEW QUESTION: 2
You are project manager of HHK project. Examine the network diagram given below:
A vendor reports that he will be four days late on the materials you'll need in order to complete Activity E.
Based on the project network diagram, how many days can Activity E be delayed?
A. Four days
B. Zero, it is on the critical path.
C. Five days
D. Six days
Answer: A
Explanation:
Explanation/Reference:
Explanation:
Answer option A is correct.
Activity E has four days of float. The entire project will take 19 days to complete. Float, or slack, in project management terms, is the amount of time an activity can be delayed without affecting any subsequent activities. There are two types of floats:
Free Float: It is the amount of time a schedule activity can be delayed without delaying the early start
date of any immediately following schedule activities.
Total Float: It is the total amount of time that a schedule activity may be delayed from its early start
date without delaying the project finish date, or violating schedule constraint.
Float is calculated by using the critical path method technique.
Answer option B is incorrect. Activity E is not on the critical path.
Answer options D and C are incorrect. These are incorrect calculations of the amount float available for Activity E.
Reference: A Guide to the Project Management Body of Knowledge, (PMBOK Guide) Chapter: Time and Cost Management Objective: Critical Path Scheduling
NEW QUESTION: 3
A wife makes outright gifts of $66,000 this year to her son, and her husband agrees to split the gifts with her. Which of the following correctly states the amount of the taxable gifts?
A. Wife $32,000, husband $32,000
B. Wife $12,000, husband $32,000
C. Wife $22,000, husband $22,000
D. Wife $44,000, husband 0
Answer: C
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