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Here are few of the sample question papers along with the answers.
NEW QUESTION: 1
Steven is using Java to write an agent in his application and needs to get a handle to the database that the agent is running in. How can Steven accomplish this?
A. Use the Session class getAgentContext method, and then make a call to the getCurrentDatabase method of the AgentContext class.
B. Use the currentDatabase property of the Session class.
C. Use the Session class getDatabase method, and then make a call to the getCurrentDatabase method of the Database class.
D. Use the getCurrentDatabase method of the Session class.
Answer: A
NEW QUESTION: 2
Your network contains an Active Directory domain named contoso.com. The domain contains two servers named Server1 and Server2 that run Windows Server 2016.
Server1 has IP Address Management (IPAM) installed. Server2 has Microsoft System Center 2016 Virtual Machine Manager (VMM) installed.
You need to integrate IPAM and VMM.
Which types of objects should you create on each server? To answer, drag the appropriate object types to the correct servers. Each object type may be used once, more than once, or not at all. You may need to drag the split bar between panes or scroll to view content.
Answer:
Explanation:
Explanation:
Server 1 (IPAM): Access Policy
VMM must be granted permission to view and modify IP address space in IPAM, and to perform remote management of the IPAM server. VMM uses a "Run As" account to provide these permissions to the IPAM network service plugin. The "Run As" account must be configured with appropriate permission on the IPAM server.
To assign permissions to the VMM user account
In the IPAM server console, in the upper navigation pane, click ACCESS CONTROL, right-click Access Policies in the lower navigation pane, and then click Add AccessPolicy.
Etc.
Server 2 (VMM) #1: Network Service
Server 2 (VMM) #2: Run As Account
Perform the following procedure using the System Center VMM console.
To configure VMM (see step 1-3, step 6-7)
Etc.
References: https://technet.microsoft.com/en-us/library/dn783349(v=ws.11).aspx
NEW QUESTION: 3
Refer to the exhibit. An attempt to deny web access to a subnet blocks all traffic from the subnet. Which interface command immediately removes the effect of ACL 102?
A. no ip access-class 102 out
B. no ip access-group 102 out
C. no ip access-group 102 in
D. no ip access-list 102 in
E. no ip access-class 102 in
Answer: B
Explanation:
Explanation/Reference:
Explanation:
Now let's find out the range of the networks on serial link:
For the network 192.168.1.62/27:
Increment: 32
Network address: 192.168.1.32
Broadcast address: 192.168.1.63
For the network 192.168.1.65/27:
Increment: 32
Network address: 192.168.1.64
Broadcast address: 192.168.1.95
-> These two IP addresses don't belong to the same network and they can't see each other
NEW QUESTION: 4
What percent of the class period is over?
(1) The time remaining is 1/4 of the time that has passed.
(2) The class period is 42 minutes long.
A. The problem can be solved using statement (1) and statement (2) TOGETHER, but not ONLY statement (1) or statement (2).
B. The problem can be solved using EITHER statement (1) only or statement (2) only.
C. The problem CANNOT be solved using statement (1) and statement (2) TOGETHER.
D. Statement (1), BY ITSELF, will suffice to solve the problem, but NOT statement (2) by itself.
E. Statement (2), BY ITSELF, will suffice to solve the problem, but NOT statement (1) by itself.
Answer: D
Explanation:
Explanation/Reference:
Explanation:
Let x equal the amount of time passed. Since the time remaining is 1/4 of the time that has passed, this time can be represented as 1/4 x. Converting to decimal form may make this problem easier, so change
1/4 x to .25x. Since 1x is the time passed and .25x is the time remaining, then 1x + .25x is the total time.
This is equal to 1.25x. To calculate the percent of the period that is over, use the proportion
Now set up a proportion using the time passed as the part and the total time for the class as the whole.
Cross-multiply to get 1.25x = 100.
Divide both sides by 1.25.
x = 80%
80% of the class period is over.
For this particular question, the number of minutes in the class period is not needed to solve the problem.
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